Physics, 17.12.2019 19:31 jaymoria16

A90.0 kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. the unstretched length of the cord is 11.0 m. she reaches the bottom of her motion 36.0 m below the bridge before bouncing back. her motion can be separated into an 11.0 m free-fall and a 25.0 m section of simple harmonic oscillation.
(a) for what time interval is she in free-fall?
(b) use the principle of conservation of energy to find the spring constant of the bungee cord.
(c) what is the location of the equilibrium point where the spring force balances the gravitational force acting on the jumper?
(d) what is the angular frequency of the oscillation?
(e) what time interval is required for the cord to stretch by 25.0 m?
(f) what is the total time interval for the entire 36.0 m drop?

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A90.0 kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. th...