This is an apparatus for studying the photoelectric effect. the work function of the material beinginvestigated is 3.810–19j. light of a wavelength 350 nm is incident on the material. what is the lowestvoltage needed between the cathode (c) and the anode (a) to stop any electrons ejected from the cathodefrom reaching the anode?

1.175 V

Explanation:

We are given that

Work function of the material= J

Wavelength of light=m

Energy of photon=Work function+Kinetic energy of electron

Where

=Wavelength of light

=Speed of light

Work function

=Small voltage

=Plank's constant

Substitute the values then we get

Hence, the lowest voltage needed between the cathode and the anode to stop any electrons ejected from the cathode from reaching the anode=1.175 V

i think if it were me i whould divide 300 dide 15

step-by-step explanation: