A44,495 kg spacecraft is traveling through space with an initial speed of 1,290 m/s relative to earth. a thruster fires for 27.4 seconds, exerting a continuous force of -1,284 n on the spacecraft. calculate the final momentum of the spacecraft.

The final momentum of the spacecraft is, p' = 57363368.4 kg m/s    

Explanation:

Given data,

The mass of the spacecraft. m = 44495 kg

The initial speed of the spacecraft, u = 1290 m/s

The thruster fires for the time, t= 27.4 s

The continuous force exerted by the thruster, F = 1284 N

The initial momentum of the spacecraft, p = mu

                              p = 44495 x 1290

                                 = 57398550 kg m/s

The final momentum of the spacecraft, p' = mv

According to newton's II law, the rate of change of momentum is equal to the force acting on the body.

                                p' = Ft + mu

                                    = -1284 x 27.4 + 57398550

                                    = 57363368.4 kg m/s

Hence, the final momentum of the spacecraft is, p' = 57363368.4 kg m/s                                                                            

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get