Gamma rays may be used to kill pathogens in ground beef. one irradiation facility uses a 60co source that has an activity of 1.0×106ci. 60co undergoes beta decay and then gives off two gamma rays, at 1.17 and 1.33 mev; typically 30% of this gamma-ray energy is absorbed by the meat. the dose required to kill all pathogens present in the beef is 4000 gy.

how many kilograms of meat per hour can be processed in this facility? express your answer in kilograms per hour.

Explanation:

Energy of gamma rays due to ore decay is

Energy of gamma ray produced in seconds is

Activity

Total energy of gamma ray produced in second is

E-energy of gamma ray produced in an hour is

Gamma ray energy absorbed by meat = 30% (in 1 hour) of E is 0.3E

Dose required to kill pathogen = 4000Gy=4000J/kg

The kilogram of meat that can be produced per hour is

The meat that can be produced =

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.