Astudent sets up an experiment to determine the inertial mass of a cart. the student has access to the following measurement equipment: a spring scale, a meterstick, and a stopwatch. the student uses the spring scale to pull the cart starting from rest along a horizontal surface such that the reading on the spring scale is always constant. all frictional forces are negligible. in addition to the spring-scale reading, which two of the following quantities could the student measure with the available equipment and then use to determine the inertial mass of the cart? select two answers.

a. the total distance traveled by the cart after it has been in motion.
b. the average speed of the cart while in motion.
c. the acceleration of the cart while in motion.
d. the time during which the cart is in motion

The correct answers are a and d

Explanation:

In this experiment it can be analyzed using Newton's second law

       F = m a

       m = F / m

The outside is supplied by the spring balance and is constant, therefore the acceleration of the system is also constant.

The acceleration can be found with the kinematic equations

      x = v t + ½ a t²

As we start from rest the initial speed is zero

      a = 2 x / t²

Therefore we need the reading of position and time.

Finally, the relationship between the balance reading and this acceleration of the mass of the system

Let's analyze the answers

a) True. It is one of the necessary quantities

b) False. With the equipment we cannot measure the speed directly

c) false. Acceleration is calculated

d) true. It is the other magnitude necessary for the calculation.

The correct answers are a and d

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach