A67.0 kg man sits in a 5.0 kg chair so that his weight is evenly distributed on the legs of the chair. assume that each leg makes contact with the floor over a circular area with a radius of 1.10 cm. what is the pressure exerted on the floor by each leg?

pressure exerted by each leg = 464,210.5 N/m^{2}

Explanation:

mass of man (Mm) = 67 kg

mass of chair (Mc) = 5 kg

radius of each leg (r) = 1.1 cm = 0.011 m

acceleration due to gravity (g) = 9.8 m/s^{2}

weight of the man = mg = 67 x 9.8 = 656.6 N

weight of the chair = mg = 5 x 9.8 = 49 N

weight of the man and chair = 656.6 + 49 = 705.6 N

since the mans weight is evenly distributed, the weight is divided evenly on the four legs. therefore

weight on each leg = 705.6 / 4 = 176.4 N

pressure exerted by each leg = force / area = weight / area

pressure exerted by each leg =

pressure exerted by each leg = 464,210.5 N/m^{2}

it is called kinetic energy

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg