You are designing a manned submersible to withstand the pressure of seawater at the bottom of the mariana trench, which is one of the deepest parts of the earth’s oceans. the bottom of the trench is at a depth of 10,900 m. part a what is the gauge pressure at this depth? (you can ignore the small changes in the density of the water with depth.)part b what is the inward force on a circular glass window 6.0 cm in diameter due to the water outside? part c if the internal pressure is 1 atm, what outward force does this produce on the window? (you may ignore the small variation in pressure over the surface of the window.)

110029941 Pa

311388.81857 N

286.48968 N

Explanation:

= Atmospheric pressure = 101325 Pa

= Density of seawater = 1029 kg/m³

h = Depth = 10900 m

g = Acceleration due to gravity = 9.81 m/s²

r = Radius = 3 cm

A = Area =

Gauge pressure

The gauge pressure is 110029941 Pa

Net pressure at the given depth

Force is given by

The force is 311388.81857 N

Now if P = 1 atm

The force is 286.48968 N

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.