In a photoelectric effect experiment you illuminate a metal with light of an unknown wavelength and measure the maximum kinetic energy of the photoelectrons to be 0.65 ev. then you illuminate the same metal with light of a wavelength known to be 2/3 of the first wavelength and measure a maximum kinetic energy of 2.3 ev for the photoelectrons.

(a) find the first wavelength, in nanometers.
(b) find the metal's work function, in electron volts.

(a). The first wavelength is 401.0 nm.

(b). The metal's work function is 2.55 eV.

Explanation:

Given that,

Maximum kinetic energy = 0.65 eV

Second wavelength

(a). We need to calculate the wavelength

Using equation of work function for first wavelength

.....(I)

For second wavelength,

Put the value of second wavelength

....(II)

By subtraction equation (I) from (II)

(b). We need to calculate the work function

Using formula of work function

Put the value into the formula

Hence, (a). The first wavelength is 401.0 nm.

(b). The metal's work function is 2.55 eV.

hello, i am papaguy.

i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!