Now consider a pipe that is stopped (i. e., closed at one end) but still has a fundamental frequency of 285 hz in air. how does your answer to part a, fhe, change? view available hint(s) now consider a pipe that is stopped (i. e., closed at one end) but still has a fundamental frequency of 285 in air. how does your answer to part a, , change? a. fhe increases. b. fhe decreases. c. fhe stays the same.

835.2267 Hz

Explanation:

M = Molar mass

= Specific heat ratio

L = Length of tube

For open ends the frequency is

For closed ends the frequency is

So,

Speed of sound is given by

So,

From the above relations we get

The frequency of helium is 835.2267 Hz

It does not matter if the tube is closed or open as

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j