Physics, 12.12.2019 21:31 emory238

A12.0-g rock is placed in a slingshot with a spring constant of 200 n/m. the rock is stretched back 0.500 m. after the slingshot is fired, what is the maximum velocity of the rock?

25.0 m/s

64.5 m/s

0.600 m/s

82.1 m/s

Answers: 3

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Answers

Answer from: lillyawesome28

The maximum velocity of the rock is 64.55 m/s

Option B

Explanation:

The possessed energy by the objects while motion called kinetic energy. It is directly proportionate to mass and square of velocity. The stored energy in the system called potential energy and expressed as below,

$\text { potential energy }=\frac{1}{2} \times(\text { spring constant }) \times\left(\text { distance from equilibrium) }^{2}\right.$

$U=\frac{1}{2} \times k \times x^{2}$

U = spring’s potential energy in certain place

k = the spring constant, in N/m.

x = the spring’s distance is stretched or compressed away from equilibrium

Conservation of energy states energy neither created nor destroyed but change from one form to other. So, using this concept, equating both potential and kinetic energies equation we get,

$\frac{1}{2} \times m \times v^{2}=\frac{1}{2} \times k \times x^{2}$

Given:

m = 12 g = 0.012 kg

k = 200 N/m

x = 0.500 m

Substitute these values we get,

$\frac{1}{2} \times 0.012 \times v^{2}=\frac{1}{2} \times 200 \times(0.500)^{2}$

$v^{2}=\frac{200 \times 0.25}{0.012}=\frac{50}{0.012}=4166.66$

Taking square root, we get,

$v=64.55 \mathrm{m} / \mathrm{s}$

Answer from: Quest

it is b

explanation:

Answer from: Quest

m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| = √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| = √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| = 14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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A12.0-g rock is placed in a slingshot with a spring constant of 200 n/m. the rock is stretched back...