A. calculate the (absolute) pressure at the bottom of a neighborhood swimming pool 30.0 m by 8.9 m whose uniform depth is 2.0 m . remember that the pressure at the top of the pool is atmospheric pressure, which (in si metric units) is 1.013×105 pa.
b. now find the (total) force exerted on the bottom of this swimming pool.
c. what is the pressure against the side of this pool (somewhere very near the bottom)?

120920 Pa

32285640 N

120920 Pa

Explanation:

= Density of water = 1000 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth = 2 m

Length = 30 m

Breadth = 8.9 m

= Atmospheric pressure =

Absolute pressure is given by

The absolute pressure is 120920 Pa

Force is given by

Force exerted on the bottom of this swimming pool is 32285640 N

Pressure is uniformly spread across the pool. So, pressure on the side of the pool is 120920 Pa

an energy transformation flow diagram is shown

where is it ?