You drag a(n) 17.4 kg steamer trunk over a rough surface by a constant force of 173 n acting at an angle of 31.5 ◦ above the horizontal. you move the trunk over a distance of 13.4 m in a straight line, and the coefficient of kinetic friction is 0.148. the acceleration of gravity is 9.8 m/s2 .

how much is the work done on the block by the net force?
answer in units of j.

1817.67 J

Explanation:

mass, m = 17.4 kg

Applied force, F = 173 N

θ = 31.5°

distance, s = 13.4 m

μ = 0.148

g = 9.8 m/s^2

According to the diagram

Let N be the normal reaction and f be the friction force.

Net force in vertical direction is zero. So, N + F Sinθ = mg

N = mg - F Sinθ

N = 17.4 x 9.8 - 173 x Sin 31.5°

N = 170.52 - 90.4

N = 80.12 N

Friction force, f = μ N = 0.148 x 80.12 = 11.86 N

net force, Fnet = F cos θ - f

F net = 173 Cos 31.5 - 11.86

F net = 135.65 N

Work don by net force

W = F net x distance

W = 135.65 x 13.4

W = 1817.67 J

Thus, the work done by the net force is 1817.67 J.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6