Acopper rod and an aluminum rod of equal diameter are joined end to end in good thermal contact. the temperature of the free end of the copper rod is held constant at 100°c, and that of the far end of the aluminum rod is held at 0°c. if the copper rod is lcu = 0.698 m long, what must be the length of the aluminum rod so that the temperature at the junction is 50.0°c?

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Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

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