Avery large magnet applies a repulsive force to a smaller (0.05 kg) magnet. if the smaller magnet accelerates across a frictionless table at 2m/s2, then what is the magnitude of the repulsive force?

Edit the post so i can see the letters for each answer, and increase the points required so i'd be able to answer it.

Indoraptor for sure

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Wow good luck with that answer