If a vehicle averages 27 mi/h on a 162 mi trip and then returns over the same 162 mi at the rate of 81 mi divided by h mi/h, what is your average speed for the trip? give reasons for your answer. write the integral that represents this information.

   1.average speed=40.5mi/hr

2.∫vdt=.∫ds

Explanation:

for the first trip= speed=distance/time

v1=s/t

27=162/t

t1=6h

for the second trip

v=s/t

81=162/t2

t2=2h

average speed=s1+s2/(t1+t2)

162+162/(2+6)

average speed=40.5mi/hr

v=ds/dt

vdt=ds..........1

integrating both sides

∫vdt=.∫ds

s=v

s=8^2/2-0^2/2

s=32+C

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the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia