Calculate the specific heat of a metal. in j/kg. k, from the following data. a container made of the metal has a mass of 3.6 kg and contains 16.0 kg of water, a 1.8 kg of the metal initially at a temperature of 171.0 °c is dropped into the water. the container and the water have an initial temperature of 16.0°c and the final temperature of the entire system is 18.0°c.

Calculate the specific heat of metal is

c = 246.47 J / kg * K

Explanation:

To calculate the specific heat of a metal

Qp = Qw + Qc

Given

m₁ = 3.6 kg, m₂ = 16.0 kg, m₃ = 1.8 kg

ΔT = 18 ° C - 16 ° C = 2 ° C

ΔTₙ = 171.0 ° C - 16 ° C = 155 ° C

m₃ * c * ΔTₙ = m₂ * c₁ * ΔT + m₁ * c₁ * ΔT

Solve to c'

c = m₂ * c₁ * ΔT  / m₃ * ΔTₙ - m₁ * ΔT

c = [ 16.0 kg * 4187 (J /kg * K) ] / [ (1.8 kg * 155° C - 3.6 kg * 2° C ) ]

c = 246.47 J / kg * K

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i believe the answer is electric potential.

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