1. a 1 kg hockey puck is moving at 10 m/s across the ice. at the other end of the ice rink, its speed is measured at 9.2 m/s. if the puck traveled 60
m, how much friction force acted on the puck? (assume the friction force was constant the whole time).

0.128 N

Explanation:

½ mv²initial = ½ mv²final + Ff d

½ (1)(10²) = ½ (1)(9.2²) + (Ff)(60)

50 = 43.32 + (Ff)(60)

7.68 = (Ff)(60)

0.128 = Ff

Note:

Ff - force of friction

1 the 4 is sig

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