Avertical spring with spring stiffness constant 305 n/m oscillates with an amplitude of 28.0 cm when 0.235 kg hangs from it. the mass passes through the equilibrium point (y=0) with positive velocity at t=0. positive direction of y-axis is downward. what equation describes this motion as a function of time?

The function that describe the motion in the time

y (t) = 0.28m * sin ( 36.025 * t)

Explanation:

The angular frequency of oscillation of the spring

w = √k/m

w = √305 N/m / 0.235 kg

w = 36.025 rad / s

To determine the function of the motion knowing as a motion oscillation in a amplitude a frequency

y(t) = A * sin (w t )

So

A = 28.0 cm * 1 m / 100 cm = 0.28 m

So replacing to determine the function of the motion in the time

y (t) = A sin (w t)

y (t) = 0.28m * sin ( 36.025 * t)

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