Acarnot engine operates between temperatures of 600 and 321 k. to improve the efficiency of the engine, it is decided either to raise the temperature of the hot reservoir by 41 k or to lower the temperature of the cold reservoir by 41 k. which change gives the greatest improvement

i think the answer is a and b

i wish you luck

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j