A500-n weight sits on the small piston of a hydraulic machine. the small piston has an area of 2.0 cm2. if the large piston has an area of 40 cm2, assume the pistons each have negligible weight

(a) how much weight can the large piston support?
(b) find the pressure applied to the pistons.

(a) Weight (Uplifting Force)=

(b) Pressure applied to piston=

Explanation:

Given Data

Force=500 N

A₁(Small Piston Area)=2.0

A₂(Large Piston Area)=40

(a) Weight=?

(b) Pressure Applied to Piston=?

Solution

First we have to Solve for part (b) Pressure

Pressure=

For Part (a) Weight

Weight (Uplifting Force)=P×A₂

Weight=250×40

Weight=10,000 N

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j