Physics, 07.12.2019 04:31 maxi12312345

Technician a says that battery straps should be used whenever a battery is lifted. technician b says that when a battery is removed, the positive cable should be disconnected first. who is correct?

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Answer from: felisha1234

The answer is neither.

Explanation:

The reason to why the answer is neither is because in order to jump start a vehicle you must:

Park the booster vehicle close to the hood of the vehicle that needs to be boosted.Set the parking brakes on both vehicles.Open the hoods of both vehicles to access the starting battery. On some vehicles this also in the trunk.Connect the clamp at the other end of the positive jumper cable (red) to the positive terminal on the battery or the jump-starting terminal.Connect the clamp at the other end of the positive jumper cable (red) to the positive terminal on the booster battery.Connect the clamp of the negative jumper cable (black) to the negative terminal on the booster battery.Connect the clamp at the other end of the negative jumper cable (black) to a piece of exposed metal part of the dead vehicle's engine and ensure that it is far away from any fuel or the battery.Run the engine of the booster vehicle for about 5 minutes.Now try to start the dead vehicle.If the vehicle does not start, check the connections of the different cables. If the engine does not start, then it should either be charged or replaced.Once the dead vehicle's engine has started, allow both vehicles to run for about 5 minutes.Then disconnect the negative cable from the vehicle and then from the booster battery.Then disconnect the positive cable from the vehicle and from the booster battery.

Answer from: Quest

distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

slope of a graph = change in value of y -axis / change in values of x -axis

comparing both the equations

change in value of y -axis = change in position

change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

Answer from: Quest

Ke reqd to move from 0 to 50 will be proportional to 50x50 or 2500. this is equal to w. to change vel from 50 to 150 you need energy prop to 22500 - 2500 = 20,000. this corresponds to 8w. best answer is a) . work reqd is prop to velocity squared.

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Technician a says that battery straps should be used whenever a battery is lifted. technician b says...