It takes 4.57 j of work to stretch a hooke’s-law spring 9.11 cm from its unstressed length. how much the extra work is required to stretch it an additional 9.54 cm? answer in units of j

Explanation:

Given that,

Work done, W = 4.57 J

Distance,

Distance,

We know that the work done by the spring is given by :

k = 550.65 N/m

To find,

Let is the extra work is required to stretch it an additional 9.54 cm. It can be calculated as :

W = 2207.96 J

So, the extra wok done is 2207.96 J.

50 inches should be the resultant vector

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.