Consider the following descriptions of the vertical motion of an object subject only to the acceleration due to gravity. begin with the acceleration equation a(t)equals=v primev′(t)equals=g, where gequals=minus−9.8 m divided by s squared9.8 m/s2.
a. find the velocity of the object for all relevant times.
b. find the position of the object for all relevant times.
c. find the time when the object reaches its highest point. what is the height?
d. find the time when the object strikes the ground. a softball is popped up vertically (from the ground) with a velocity of 27 m divided by s27 m/s.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

i think the answer would be reserve.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.