The 1.30-kg head of a hammer has a speed of 7.3 m/s just before it strikes a nail and is brought to rest estimate the temperature rise of a 14-g iron nail generated by 8.0 such hammer blows done in quick succession. assume the nail absorbs all the energy. the specific heat of iron is 450 j/kg⋅c∘.

The rise in temperature is

Solution:

As per the question:

Mass of hammer, M = 1.30 kg

Speed of hammer, v = 7.3 m/s

Mass of iron,

No. of blows, n = 8

Specific heat of iron,

Now,

To calculate the temperature rise:

Transfer of energy in a blow = Change in the Kinetic energy

For 8 such blows:

Now, we know that:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.