You charge a parallel-plate capacitor, remove it from the battery, and prevent the wires connected to the plates from touching each other. when you pull the plates apart to a larger separation, do the following quantities increase, decrease or stay the same? i) cii) qiii) e between the platesiv) delta v

i) C decreases

ii) Q remains constant

iii) E remains constant

iv) ΔV increases

Explanation:

i)

We know, capacitance is given by:

In this case as the distance between the plates increases the capacitance decreases while area and permittivity of free space remains constant.

ii)

As the amount of charge has nothing to do with the plate separation in case of an open circuit hence the charge Q remains constant.

iii)

Electric field between the plates is given as:

where:

charge density,

As we know that distance of plate separation cannot affect area of the plate. Charge Q and permittivity are also not affected by it, so E remains constant.

iv)

answer is c

explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.