The diffusion constant for oxygen diffusing through tissue is 1.0 × 10-11 m2/s. in a certain sample oxygen flows through the tissue at 2.0 × 10-6 kg/s. if the thickness of the tissue is doubled, then what is the rate of oxygen flow through the tissue?

m' = 1 x 10⁻⁶ kg/s

Explanation:

Given that

Diffussion constant = 1 x 10⁻¹¹

Mass flow rate ,m = 2 x 10⁻⁶ kg/s

The diffusion is inversely proportional to the thickness of the membrane and therefore when the thickness is doubled, the mass flow rate would become half.

So new flow rate m'

m' = 1 x 10⁻⁶ kg/s

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

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