The objective lens and the eyepiece lens of a telescope are 1.0 m apart. the telescope has an angular magnification of 45. part a find the focal length of the eyepiece. express your answer with the appropriate units. fef e = nothing nothing request answer part b find the focal length of the objective. express your answer with the appropriate units. fof o = nothing nothing

(A) 0.0217 m

(B) 0.9765 m

Explanation:

Distance between the objective lens and the eye piece, d = 1.0 m

Angular magnification, m = 45

Now,

(A) To calculate the focal length of objective:

where

= focal length of object

= focal length of eye piece

Thus

             (1)

From eqn (1):

(B) To calculate the focal length of eye piece:

From eqn (1):

what was the answer?

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~