A95 n force exerted at the end of a 0.50 m long torque wrench gives rise to a torque of 15 nm. what is the angel (assumed to be less than 90 degrees) between the wrench handle and the direction the force is applied?

9.1°

Explanation:

Torque = distance from pivot * perpendicular force

15 Nm = 0.5 m * perpendicular force

perpendicular force  = 30 N

So the bertical component of the applied force that caused a turning  effect (torque) was 30 N. Now we use this information to find the angle that would produce a vertical component of  30N from an applied force of 95 N.

Fy = FSinθ

15 = 95 Sinθ

θ = 9.1°

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