Problem 11.010 is a rigid tank contains 1 kg of oxygen (o2) at p1 = 30 bar, t1 = 180 k. the gas is cooled until the temperature drops to 150 k. determine the volume of the tank, in m3, and the final pressure, in bar, using the:

Explanation:

The gas law relation is

PV = nRT where n is no of moles of gas

given 1 kg of oxygen

n = 1000 / 32 = 31.25 moles

P = 30 bar = 30 x 10⁵ Pa

V =?

T = 180 K

R = 8.32

Substituting the values

30 x 10⁵ x V = 31.25 x 8.32 x 180

V = 1560 x 10⁻⁵ m³

= 1.56 x 10⁻² m³

When volume remains constant , pressure is proportional to temperature

P₂ / P₁ = T₂ / T₁

P₂ =  ( 150 / 180 ) x 30

= 25 Bar.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

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