Written:
1) an 8.5 x 102 kg elevator is pulled up at a constant velocity of 1.00 m/s by a motor
that consumes 10.0 kw of power. calculate the efficiency of the motor.

0.833

Explanation:

Power = energy / time

Power = force × distance / time

Power = force × velocity

P = (850 kg) (9.8 m/s²) (1.00 m/s)

P = 8330 W

P = 8.33 kW

The efficiency of the motor is therefore:

e = 8.33 kW / 10.0 kW

e = 0.833

what are the statements? x

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever