An archer puts a 0.4 kg arrow to the bowstring. an average force of 190.4 n is exerted to draw the string back 1.47 m. the acceleration of gravity is 9.8 m/s². assuming no frictional loss, with what speed does the arrow leave the bow? answer in units of m/s. if the arrow is shot straight up, how high does it rise? answer in units of m.

Answer: 1.4 seconds which is the third optionexplanation: current is defined as the flow of charge per timetherefore, the equation that relates current, charge and time can be expressed as follows: i = δq / δtwhere: i is the current given = 1.8 ampereδq is the charge given = 2.5 coulombδt is the time required for the flow of the given charges to give the 1.8 ampere.substitute with the givens in the above equation to get the time as follows: 1.8 = 2.5 / δtδt = 2.5 / 1.8 = 1.38888 which is approximately 1.4 secondshope this was !

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