Ashopper pushes a 5.32 kg grocery cart
with a 12.7 n force directed at -28.7°. a friction
force of 8.33 n pushes back against the motion.
what is the acceleration of the cart?

Explanation:

According to “Newton's second law”

“Force” is “mass” times “acceleration”, or F = m× a. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass

Force = mass × acceleration

Given that,

Mass = 5.32 kg

F = 12.7N

Normal force = mg + F sinx,  

“m” being the object's "mass",  

“g” being the "acceleration of gravity",

“x” being the "angle of the cart"

To find normal force substitute the values in the formula,

Normal force = 5.32 × 9.8 + 12.7 × sin(-28.7)

Normal force = 52.136 + 12.7 × 0.480

Normal force = 52.136 + 6.096

Normal force = 58.232 N

Acceleration of the cart:

v 154.9= 0.9 length length s little over 154.9cm

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