Arace car accelerates from 0 m/s to 30.0 m/s with a displacement of .25 km. what is the vehicle's acceleration?

The acceleration of the car, a = 60 m/s²

Explanation:

Given data,

The initial velocity of the car, u = 0 m/s

The final velocity of the car, v = 30 m/s

The displacement of the car, s = 0.25 km

Using the III equations of motion

                    v² = u² + 2as

                     a = (v² - u²) / 2s

                        = 30 / 2 x 0.25

                        = 60 m/s²

Hence, the acceleration of the car, a = 60 m/s²

car a and b are moving in opposite directions

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when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min