Aworld class sprinter can accelerate at 5.0 m/s squared, from the rest in the starting blocks to their top speed in 4.0 seconds. what distance will such a sprinter cover during that time?

The distance covered by the sprinter, s = 40 m

Explanation:

Given data,  

The initial velocity of the sprinter, u = 0 m/s

The acceleration of the sprinter, a = 5 m/s²

The time period of acceleration of the sprinter, t = 4 s

Using the II equations of motion

                   s = ut + ½ at²

                       = 0 + ½ (5) (4)²

                       = 40 m

Hence, the distance covered by the sprinter, s = 40 m                    

0.11 m/s and 0.28 m/s should be correct

not moving. pos accel,