An 80.0-kg object is falling and experiences a drag force due to air resistance. the magnitude of this drag force depends on its speed, v, and obeys the equation fdrag=(12.0n⋅s/m)v+(4.00n⋅s2/m2)v2. what is the terminal speed of this object? a. 72.2 m/sb. 12.6 m/sc. 47.3 m/sd. 34.2 m/se. 6.45 m/s

The terminal speed of this object is 12.6 m/s

Explanation:

It is given that,

Mass of the object, m = 80 kg

The magnitude of drag force is,

The terminal speed of an object is attained when the gravitational force is balanced by the gravitational force.

On solving the above quadratic equation, we get two values of v as :

v = 12.58 m/s

v = -15.58 m/s (not possible)

So, the terminal speed of this object is 12.6 m/s. Hence, this is the required solution.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2