:a 10 g bullet travelling at 300 m/s hits a 500 g wooden block that is initially stationary. the bullet becomes embedded in the block, and both travel together along a frictioneless surface. answer each of the following questions a) what is the kinetic energy of the bullet before it hits the block? b) what is the velocity of the bullet+block after the collision?

450 J

5.88235 m/s

Explanation:

The kinetic energy is given by

The kinetic energy of the bullet before it hits the block is 450 J

= Mass of bullet = 0.01 kg

= Mass of block = 0.5 kg

= Initial Velocity of bullet = 300 m/s

= Initial Velocity of second block = 0 m/s

v = Velocity of combined mass

In this system the linear momentum is conserved

The velocity of the bullet+block after the collision is 5.88235 m/s

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min