Aparticle with charge q and kinetic energy ke travels in a uniform magnetic field of magnitude b. if the particle moves in a circular path of radius r, find expressions for its speed v and its mass m. (use any variable or symbol stated above as necessary.) (a) expression for its speed (do not use m in your answer.) v = (b) expression for its mass (do not use v in your answer.) m =

a)

b)

Explanation:

Given that

Charge = q

Magnetic filed = B

Radius = R

We know that kinetic energy KE

                   ----------1

m v² = 2 .KE            

The magnetic force F = q v B

Radial force

For uniform force these two forces should be equal

q v B R =m v²

q v B R =  2 .KE

Now put the velocity v in the equation

a lot of it means it can be "burned" for energy and sold at one price. if it is scarce, the price will go up

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.