1) a slab-milling operation will take place on a part 300 mm long and 40 mm wide. a helical cutter 75 mm in diameter with 10 teeth will be used. if the feed per tooth is 0.2 mm/tooth and the cutting speed is 0.75 m/s, find the machining time and metal-removal rate for removing 6 mm from the surface of the part.2) refer to the following and assume that d = 150 mm, w = 60 mm, l = 500 mm, d = 3 mm, v = 0.6 m/min, and n = 100 rpm. the cutter has 10 inserts, and the workpiece material is a high-strength aluminum alloy. calculate the material removal rate, cutting time and feed per tooth.

the independent variable, or the one that is intentionally manipulated is the speed.

c

explanation:

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

no. dot product   =0 when vecs at right angles