Two identical strings, of identical lengths of 2.00 m and linear mass density of μ=0.0065kg/m, are fixed on both ends. string a is under a tension of 120.00 n. string b is under a tension of 130.00 n. they are each plucked and produce sound at the n=10 mode. what is the beat frequency?

beat frequency = 13.87 Hz

Explanation:

given data

lengths l = 2.00 m

linear mass density μ = 0.0065 kg/m

String A is under a tension T1 = 120.00 N

String B is under a tension T2 = 130.00 N

n = 10 mode

to find out

beat frequency

solution

we know here that length L is

L = n ×      ........1

so  λ =  

and velocity is express as

V =    .................2

so

frequency for string A = f1 =

f1 =

f1 =      

and

f2 =

so

beat frequency is = f2 - f1

put here value

beat frequency =  -

beat frequency = 13.87 Hz

f is prop to m1xm2 double m1 double force