How fast does a 3 kg rocket accelerate if a force of 140 n is applied?

46.67 m/s²

We are given;

we are supposed to calculate the acceleration of the rocket;

Therefore;

F = Ma

In this case;

Rearranging the formula

a = F ÷ m

  = 140 N ÷ 3 kg

  = 46.67 m/s²

Thus, the acceleration of the rocket is 46.67 m/s²

c

explanation:

i believe the answer is c and this is only worth 10 points you might wanna change it

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation