An 86.0-kg climber is scaling the vertical wall of a mountain. his safety rope is made of nylon that, when stretched, behaves like a spring with a spring constant of 1.20 × 10³ n/m. he accidentally slips and falls freely for 0.750 m before the rope runs out of slack. how much is the rope stretched when it breaks his fall and momentarily brings him to rest?

x = 1.95 m

Explanation:

As we know that total mechanical energy is conserved here

So gravitational potential energy of the climber will convert into spring potential energy

So we will have

here we know that

m = 86 kg

L = 0.750 m

now we will have

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