Solution g a square loop is halfway into a magnetic field that is perpendicular to the plane of the loop. the loop mass is 10 g and its resistance is 0.020 ω . a switch is closed at t =0s, causing the magnetic field to increase from 0 to 1.0 t in 0.010 s. a) what is the induced current in the square loop? bwith what speed is the loop "kicked" away from the magnetic field? hint: what is the impulse on the loop?

Explanation:

It is given that,

Mass of the loop, m = 10 g = 0.01 kg

Resistance of the loop, R = 0.02 ohms

Dimension of square loop, 7 cm × 7 cm

Area of the loop,

At time t = 0 s, the magnetic field increases from 0 to 1 T in 0.01 s

(a) Due to change in magnetic field, an emf is induced in the loop. Using the formula for induced emf as :

Now using Ohm's law to find the induced current in the loop. It is given by :

I =24.5 A

(b) A magnetic force acting on the loop is given by :

F = 0.8575

Since,

v = 0.8575 m/s

Hence, this is the require solution.

answer: i pick a

explanation:

explanation:

a fuel engine ( known as a gasoline engine in american english )is an internal combustion engine with spark ignition, designed to run on petrol (gasoline) and similar volatile fuels.