The self inductance relates the magnetic flux linkage to the current through the coil. calculate the self inductance l in units of μh. the coil is d = 5 cm long and has a cross-sectional area of a = 3 cm2 and consists of n = 130 turns.

Self inductance,

Explanation:

It is given that,

Length of the coil, l = 5 cm = 0.05 m

Area of cross section of the coil,

Number of turns in the coil, N = 130

The self inductance relates the magnetic flux linkage to the current through the coil and it is given by :

L = 0.000127 Henry

or

So, the self inductance of the coil is 127 microhenry. Hence, this is the required solution.

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