An electron is accelerated through 2.70 103 v from rest and then enters a uniform 1.40-t magnetic field. (a) what is the maximum magnitude of the magnetic force this particle can experience?

To solve the exercise it is necessary to apply the concepts of Mangenetic Force and Energy generated by electric potential.

By definition we know that the energy within an electron through voltage can be expressed as

Where,

e= charge of electron

V= Voltage

The kinetic energy of a moving system can be expressed as

Where,

m = mass

v = Velocity

For energy conservation we have to

Solving to find v,

On the other hand we have that the Magnetic Force can be expressed as,

Where,

q=charge of proton

v=velocity

B= Magnetic field

Angle between the magnetic field and the velocity vector (It is perpendicular in this case)

Using the previous equation from velocity in the Force equation we have,

PART A) Replacing the values to find the force we have,

mass and volume are the answers you are looking for

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .