(b) an example of an inverse square field is the gravitational field f = −(mmg)r/|r|3. use part (a) to find the work done by the gravitational field when the earth moves from aphelion (at a maximum distance of 1.52 108 km from the sun) to perihelion (at a minimum distance of 1.47 108 km). use the values m = 5.97 1024 kg, m = 1.99 1030 kg, and g = 6.67 ✕ 10−11 n·m2/kg2. (round your answer to two decimal places.)

To solve this, we need to recall that Work done W,

W = F x dₐ                         Eqn 1

where F is the gravitational field force and d is the distance travelled by the earth.

But F = −(mMG)r/|r|³                    Eqn 2

then, W = −∫ (mMG)r/|r|³ x dₐ

Integrating this expression gives us

W = -4mMG ((1/d1) -(1/d2))

m = 5.971024 kg, M = 1.991030 kg G = 6.67 ✕ 10⁻¹¹ N·m²/kg²

d2 = 1.52x10¹¹m, d1 = 1.47x10¹¹m  make the units in S.I units and similar

Substituting these value in to the eqn above gives

Now , W = 1.77 x 10³²J  (2 Decimal Places)

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.