Acarbon resistor is 5 mm long and hasa constant cross section of 0.5mm2. the conductivity of carbon at room temperature is = 3104 per ohm·m. in a circuit itspotential at one end of the resistor is 13 volts relative to ground, and at the other endthe potential is 17 volts. calculatethe resistance r and the current i. r = .333correct check mark0.333i =12.01amperesexplane how to work this problem with the actualwork.

Explanation:

The given data is as follows.

       l = 5 mm = m,   A = 0.5 =

 conductivity () = per ohm-m

      = 13 volts,       = 17 volts

Now, the relation between conductivity and resistivity is as follows.

where,     = resistivity

Therefore, calculate resistivity as follows.

                            = ohm-m          

Now, we will calculate the resistance using the following formula.

                 R =

                      =

                      = 0.333 ohm

Hence, value of resistance is 0.333 ohm.

As we know that relation between current and voltage is as follows.

                           V = IR

Therefore, calculate the value of current as follows.

                         V = IR

                  (17 - 13) =

                    I = 12.01 ampere

Thus, value of the current is 12.01 A.

c) up is the direction the magnetic force is acting on the charge.