At a time t= 3.40s , a point on the rim of a wheel with a radius of 0.210m has a tangential speed of 53.0m/s as the wheel slows down with a tangential acceleration of constant magnitude 11.0m/s2 .
part a
calculate the wheel's constant angular acceleration.
part b
calculate the angular velocity at t = 3.40s .
part c
calculate the angular velocity at t=0.
part d
through what angle did the wheel turn between t=0 and t = 3.40s ?
part e
prior to the wheel coming to rest, at what time will the radial acceleration at a point on the rim equal g = 9.81m/s2 ?
Answers: 2
Physics, 22.06.2019 03:50, ash011519
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Physics, 22.06.2019 15:00, sswd
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