Two friends are pushing a stalled,
1610 kg car. the first pushes with
a 107 n forward force. the car
accelerates at 0.123 m/s . how much
force does the second person exert?
(unit = n)

91.03 N

Explanation:

consider the way the forces are acting on the car , in the graph

assume the car is accelerating to the right

we can apply Newton's second law of motion (F = ma )

→ F = ma

Fpush + 107 = 1610 * 0.123

Fpush = 91.03 N

second guy is applying 91.03 N force on the car

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.