A1500-kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2200-kg suv traveling from east to west. the two cars become enmeshed due to the impact and slide as one thereafter. on-the-scene measurements show that the coefficient of kinetic friction between the tires of these cars and the pavement is 0.75, and the cars slide to a halt at a point 5.39 m west and 6.43 m south of the impact point. how fast was each car traveling just before the collision?

Velocity of Sedan = 21 m/s

Velocity of SUV = 12 m/s

Explanation:

As we know that deceleration due to friction force is given as

so we have

now the two cars comes to rest at a point which is at position of 5.39 m West and 6.43 m South

so net displacement of the car is given as

now the velocity of the two cars just after the impact is given as

direction of the motion is given as

South of West

now we can use momentum conservation as there is no external force on it

Momentum conservation in North to south direction

Similarly momentum conservation towards West direction

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this