In a test strength at a carnival, a hammer drives a metal weight up a rod to ring a bell at the top. if the bell is 24 ft above the starting position of the weight, what is the minimum initial vertical velocity needed to ring the bell?

39 ft/s

Explanation:

Given:

Δy = 24 ft

v = 0 ft/s

a = -32 ft/s²

Find: v₀

v² = v₀² + 2aΔy

(0 ft/s)² = v₀² + 2 (-32 ft/s²) (24 ft)

v₀ ≈ 39 ft/s

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